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Using the identity (2m, m² − 1, m² + 1) for Pythagorean triplets, the triplet generated by m = 4 is:
A(7, 24, 25)
B(8, 15, 17)
C(9, 12, 15)
D(5, 12, 13)
Answer & Solution
Correct answer: B. (8, 15, 17)
With m = 4: 2m = 8, m² − 1 = 16 − 1 = 15, m² + 1 = 16 + 1 = 17. So the triplet is (8, 15, 17). Verify: 8² + 15² = 64 + 225 = 289 = 17² ✓
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