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From the top of a 75 m tower, the angles of depression of two cars on the road on opposite sides of the tower are 30 degrees and 60 degrees. The distance between the cars is
A100 m
B75 ((square root of 3) + 1/(square root of 3)) m
C125 m
D150 m
Answer & Solution
Correct answer: B. 75 ((square root of 3) + 1/(square root of 3)) m
1. Far car at 30 degrees: distance d1 = 75/tan(30) = 75 (square root of 3).
2. Near car at 60 degrees: distance d2 = 75/tan(60) = 75/(square root of 3).
3. Total = 75 (square root of 3) + 75/(square root of 3) m.
_Source: NCERT Class 10 Mathematics, Ch 9 "Some Applications of Trigonometry", §9.2_
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