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The sum of the interior angles of a polygon with n sides is:
A(n − 2) × 180°
Bn × 180°
C(n − 1) × 180°
D360°
Answer & Solution
Correct answer: A. (n − 2) × 180°
A polygon with n sides can be divided into (n − 2) triangles by drawing diagonals from one vertex. Each triangle has angles summing to 180°, so the total interior-angle sum is (n − 2) × 180°. For n = 3 (triangle): 180°. For n = 4 (quadrilateral): 360°. For n = 5 (pentagon): 540°.
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