A galvanometer of resistance 60.00 Ω is used to measure current in a circuit with a 3 V source and a 3 Ω resistor. Used directly as the meter, the current reading is:

1. The galvanometer adds its full resistance in series with the 3 Ω resistor. 2. Total resistance: $R_G + 3 = 60 + 3 = 63\ \Omega$. 3. Current: $I = \dfrac{V}{R} = \dfrac{3}{63}$. 4. $I = 0.048$ A — far below the true value, showing why a bare galvanometer disturbs the circuit. _Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", p.161_