A long straight wire carries a current of 35 A. The magnitude of the magnetic field at a point 20 cm from the wire is:
A1.75 × 10⁻⁵ T
B7.0 × 10⁻⁵ T
C3.5 × 10⁻⁵ T
D3.5 × 10⁻⁴ T
Answer & Solution
Correct answer: C. 3.5 × 10⁻⁵ T
1. Field of a long straight wire: $B = \dfrac{\mu_0 I}{2\pi r}$.
2. Write $\dfrac{\mu_0}{2\pi} = 2\times10^{-7}$ T m A⁻¹.
3. Substitute $I = 35$ A, $r = 0.20$ m: $B = \dfrac{2\times10^{-7}\times35}{0.20}$.
4. Numerator $= 7\times10^{-6}$; dividing by 0.20 gives $B = 3.5\times10^{-5}$ T.
_Source: syllabus Physics Ch 4 "Moving Charges and Magnetism", p.158_
Keep practising Moving Charges and Magnetism
Browse all Moving Charges and Magnetism questions for ISC Class 12, or explore more Physics topics.
Related questions
The magnetic field at a distance $r$ from a LONG STRAIGHT wire carrying current $I$ isThe magnetic force on a charge $q$ moving with velocity $\vec{v}$ in a magnetic field $\veMatch the magnetism termWork done by a magnetic forceNEET · Physics · Magnetic Formula ↔ QuantityA bismuth bar near a strong magnet on the lab table is:Materials are classified by which quantity?Magnetic field lines of a bar magnet form: