Home › ISC Class 12 › Physics › Moving Charges and Magnetism › Ampère's circuital law for a closed loop boundin…
Ampère's circuital law for a closed loop bounding a surface carrying total current I is correctly stated as:
A∮ B · dl = μ₀ I²
B∮ B · dl = μ₀ / I
C∮ B · dl = I / μ₀
D∮ B · dl = μ₀ I
Answer & Solution
Correct answer: D. ∮ B · dl = μ₀ I
1. Ampère's law relates the line integral of B around a closed loop to the enclosed current.
2. The integral $\oint \mathbf{B}\cdot d\mathbf{l}$ is taken over the boundary of the surface.
3. The law states this equals $\mu_0$ times the total current through the surface.
4. Hence $\oint \mathbf{B}\cdot d\mathbf{l} = \mu_0 I$.
_Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", p.149_
Related questions
An electron and a proton enter a magnetic field with the same kinetic energy, perpendiculaA galvanometer is converted into an ammeter of higher range by connecting:The work done by a static magnetic force on a moving charge is:Magnetic field at a point on the axis of a circular loop, far from the loop (distance x ≫ The dimensional formula of the magnetic field B (in SI units of tesla) is:A cyclotron of magnetic field B accelerates positive charges of mass m, charge q. The cyclTorque on a magnetic dipole (current loop) of moment m placed in a uniform field B at anglTwo long parallel wires carry currents I₁ and I₂ in the SAME direction, separated by dista