The sum of three consecutive **even** integers is $66$. What is the **largest** of the three?
A$22$
B$24$
C$26$
D$20$
Answer & Solution
Correct answer: B. $24$
Three consecutive even integers can be written as $n, n+2, n+4$ (all even if $n$ is even).
$n + (n+2) + (n+4) = 66 \Rightarrow 3n + 6 = 66 \Rightarrow n = 20$.
Integers: $20, 22, 24$. Largest $= 24$.
- Trap A is the smallest.
- Trap B is the middle.
Related questions
GMAT DS questions should be paced at:The sum of 5 consecutive integers is always divisible by:If x² = 36, what can we conclude about x?A GMAT PS question asks: 'What is x if 3x + 5 = 23?' Options: 4, 5, 6, 7. The fastest apprOn a percentage question with abstract values, the recommended smart-number to assume is:Is 1,287 divisible by 3?In a GMAT DS question, what is the FIRST step?In GMAT DS, answer choice (A) is selected when: