A particle of charge q and mass m undergoes circular motion in a uniform magnetic field B. Its frequency of revolution (cyclotron frequency) is:

1. The angular frequency of the circular motion is $\omega = \dfrac{qB}{m}$. 2. Frequency relates to angular frequency by $\omega = 2\pi\nu$. 3. Therefore $\nu_c = \dfrac{\omega}{2\pi} = \dfrac{qB}{2\pi m}$. 4. This is independent of the particle's speed and radius, which is exploited in the cyclotron. _Source: syllabus Physics Ch 4 "Moving Charges and Magnetism", p.156_