alleryThe value of log(75/16) - 2 log(5/9) + log(32/243) is
Alog 3
B1
Clog 2
D0
Answer & Solution
Correct answer: C. log 2
1. 2 log(5/9) = log(25/81), so the middle term becomes -log(25/81).
2. Combine: log(75/16) + log(81/25) + log(32/243).
3. Multiply arguments: (75*81*32) / (16*25*243) = (75*81*32) / (16*25*243).
4. Compute numerator 75*81*32 = 194400; denominator 16*25*243 = 97200; ratio = 2; so log 2.
_Source: ICAI BoS Foundation Paper 3, Ch 1 Unit IV 'Logarithms', p.18_
Keep practising Basic Arithmetic
Browse all Basic Arithmetic questions for CA Foundation, or explore more Quantitative Aptitude topics.
Related questions
If 25% of a number plus 15 equals 40, the number isThe mean proportional between 4 and 16 equalsIf log a equals zero, the value of a isIf a : b = c : d, then by alternendo, the relation a : c = b : d meansThe value of x^(a-b) * x^(b-c) * x^(c-a) for any non-zero x isThe duplicate ratio of 3 : 4 isThe inverse ratio of 11 : 15 isIf a, b, c, d are in proportion (a : b :: c : d), then by componendo and dividendo, (a + b