Among the eight planets, the *closest* and *farthest* distances from the Sun (in millions of km) for Neptune are $4{,}450$ and $4{,}550$. What is the *average* of Neptune's closest and farthest distances?
A$4{,}550$
B$4{,}450$
C$4{,}500$
D$9{,}000$
Answer & Solution
Correct answer: C. $4{,}500$
$\dfrac{4{,}450 + 4{,}550}{2} = \dfrac{9{,}000}{2} = 4{,}500$.
- Trap D returns the sum without averaging.
- Trap A and C restate the input values.
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