The relationship between **edge length $a$** and **atomic radius $r$** in a **body-centred cubic (bcc)** unit cell is:
A$a = 2r$
B$a = 4r/\sqrt 3$
C$a = 4r/\sqrt 2$
D$a = r\sqrt 3$
Answer & Solution
Correct answer: B. $a = 4r/\sqrt 3$
In bcc, body diagonal $= a\sqrt 3 = 4r$ (along it: corner atom + central atom + corner atom = 4r in radii). So $a = 4r/\sqrt 3$.
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