The density of a cubic crystal is given by:
A$\rho = nM/(a^3 N_A)$
B$\rho = a^3 N_A/(nM)$
C$\rho = nM \cdot a^3 \cdot N_A$
D$\rho = M / a^3$
Answer & Solution
Correct answer: A. $\rho = nM/(a^3 N_A)$
Density $\rho$ = mass/volume = $(n \times M/N_A)/a^3 = nM/(a^3 N_A)$, where $n$ = particles per unit cell, $M$ = molar mass, $a$ = edge length, $N_A$ = Avogadro's number.
Related questions
A pure semiconductor at absolute zero temperature behaves asF-centres are responsible for the colour of crystals such as NaCl heated in sodium vapour Schottky defect lowers the density of the crystal becauseA Frenkel defect involvesPacking efficiency of a simple cubic (SC) arrangement is approximatelyCoordination number of an atom in an FCC lattice isThe relation between edge length a and radius r of an atom in BCC arrangement isIn a face-centred cubic (FCC) cell, total number of effective atoms is