Start learning →

The condition for **terminal velocity** of a sphere falling in a viscous fluid is that:

AViscous force exceeds gravity
BNet force is zero: weight = viscous drag + buoyant force
CThe fluid is at rest
DGravity is zero
Answer & Solution
Correct answer: B. Net force is zero: weight = viscous drag + buoyant force
At terminal velocity, sphere falls at constant speed: net force = 0. $mg = 6\pi\eta r v_t + (4/3)\pi r^3 \sigma g$ (sphere weight = viscous drag + upthrust). Solving gives $v_t = (2/9)r^2(\rho - \sigma)g/\eta$.
Practise this question with Quill — AP Physics 1 →

Keep practising Unit 1A: Kinematics: 1D Motion, Position & Velocity

Browse all Unit 1A: Kinematics: 1D Motion, Position & Velocity questions for AP Physics 1, or explore more Physics topics.

Start a Unit 1A: Kinematics: 1D Motion, Position & Velocity lesson →