alleryThe pressure $p$ at depth $h$ below the free surface of a liquid of density $\rho$ (in addition to atmospheric pressure $p_0$) is:
A$p = p_0 - h\rho g$
B$p = p_0 + h\rho g$
C$p = h\rho g$ only
D$p = p_0 / (h\rho g)$
Answer & Solution
Correct answer: B. $p = p_0 + h\rho g$
Total pressure (absolute) at depth $h$ = atmospheric + liquid column pressure = $p_0 + h\rho g$.
Gauge pressure is just $h\rho g$ (excluding $p_0$).
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