Convert the mixed number $4\tfrac{3}{8}$ to an improper fraction.
A$\dfrac{35}{8}$
B$\dfrac{43}{8}$
C$\dfrac{15}{8}$
D$\dfrac{12}{8}$
Answer & Solution
Correct answer: A. $\dfrac{35}{8}$
A mixed number $a\tfrac{b}{c}$ converts to $\dfrac{a \cdot c + b}{c}$.
$4\tfrac{3}{8} = \dfrac{4 \cdot 8 + 3}{8} = \dfrac{32 + 3}{8} = \dfrac{35}{8}$.
- Trap D mistakenly concatenates digits: $4 \to 4$, $3 \to 3$ giving $43$.
- Traps A and B miscompute the numerator.
Related questions
GMAT DS questions should be paced at:The sum of 5 consecutive integers is always divisible by:If x² = 36, what can we conclude about x?A GMAT PS question asks: 'What is x if 3x + 5 = 23?' Options: 4, 5, 6, 7. The fastest apprOn a percentage question with abstract values, the recommended smart-number to assume is:Is 1,287 divisible by 3?In a GMAT DS question, what is the FIRST step?In GMAT DS, answer choice (A) is selected when: