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Convert the mixed number $4\tfrac{3}{8}$ to an improper fraction.

A$\dfrac{35}{8}$
B$\dfrac{43}{8}$
C$\dfrac{15}{8}$
D$\dfrac{12}{8}$
Answer & Solution
Correct answer: A. $\dfrac{35}{8}$
A mixed number $a\tfrac{b}{c}$ converts to $\dfrac{a \cdot c + b}{c}$. $4\tfrac{3}{8} = \dfrac{4 \cdot 8 + 3}{8} = \dfrac{32 + 3}{8} = \dfrac{35}{8}$. - Trap D mistakenly concatenates digits: $4 \to 4$, $3 \to 3$ giving $43$. - Traps A and B miscompute the numerator.
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