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Find the **midpoint** of the segment connecting $A(-4, 6)$ and $B(8, -2)$.

A$(2, 2)$
B$(2, 4)$
C$(4, 2)$
D$(6, 4)$
Answer & Solution
Correct answer: A. $(2, 2)$
Midpoint formula: $\left(\dfrac{x_{1} + x_{2}}{2},\, \dfrac{y_{1} + y_{2}}{2}\right)$. $= \left(\dfrac{-4 + 8}{2},\, \dfrac{6 + (-2)}{2}\right) = \left(\dfrac{4}{2},\, \dfrac{4}{2}\right) = (2, 2)$. - Trap B forgets to average $y$. - Trap C swaps the order of operations. - Trap D returns the sum, not the average.
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