The line with equation $y = \tfrac{1}{3}x + 2$ crosses the $x$-axis at what $x$-value?
A$-6$
B$-2$
C$\dfrac{1}{3}$
D$2$
Answer & Solution
Correct answer: A. $-6$
At the $x$-axis, $y = 0$. Set $0 = \tfrac{1}{3}x + 2 \Rightarrow \tfrac{1}{3}x = -2 \Rightarrow x = -6$.
- Trap D ($2$) gives the $y$-intercept (where $x = 0$), not the $x$-intercept.
- Trap B ($-2$) drops the factor.
- Trap C confuses the slope with the intercept.
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