For the reaction 2HI(g) → H₂(g) + I₂(g), the rate of reaction is:
A+Δ[HI]/Δt
B2 × Δ[H₂]/Δt
C−Δ[HI]/Δt
D−½ × Δ[HI]/Δt = +Δ[H₂]/Δt = +Δ[I₂]/Δt
Answer & Solution
Correct answer: D. −½ × Δ[HI]/Δt = +Δ[H₂]/Δt = +Δ[I₂]/Δt
Rate must be defined the same way regardless of which species you track. With a 2:1:1 stoichiometry, divide each ΔC/Δt by its stoichiometric coefficient: r = **−(1/2) Δ[HI]/Δt = +Δ[H₂]/Δt = +Δ[I₂]/Δt**.
Related questions
It is observed that for many reactions the rate constant nearly doubles for a rise in tempThe half-life for the radioactive decay of carbon-14 is 5730 years and decay is first ordeIn a pseudo first order reaction, [A]/mol L^-1 reads 0.31 at t = 30 s and 0.17 at t = 60 sIn collision theory, what is meant by the collision frequency (Z)?According to collision theory, in the modified rate expression Rate = P Z_AB e^(-Ea/RT), wHow does a catalyst increase the rate of a chemical reaction?The first order rate constant for decomposition of ethyl iodide is 1.60 x 10^-5 s^-1 at 60The rate constants of a reaction at 500 K and 700 K are 0.02 s^-1 and 0.07 s^-1 respective