Home › UP Board Class 12 › Physics › Moving Charges and Magnetism › A cyclotron of dee radius R accelerates ions of …
A cyclotron of dee radius R accelerates ions of charge q, mass m in a magnetic field B. The maximum kinetic energy is
AqBR
Bq²B²R²/(2m)
CqBR²/(2m)
Dq²B²/(2mR)
Answer & Solution
Correct answer: B. q²B²R²/(2m)
1. At the edge of the dees, the orbit radius equals R: qvB = mv²/R gives v_max = qBR/m.
2. Kinetic energy K = ½ m v_max².
3. Substitute v_max: K = ½ m (qBR/m)².
4. Simplify: K = q²B²R²/(2m). This is the maximum extracted KE.
_Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", §4.4.2_
Related questions
An electron and a proton enter a magnetic field with the same kinetic energy, perpendiculaA galvanometer is converted into an ammeter of higher range by connecting:The work done by a static magnetic force on a moving charge is:Magnetic field at a point on the axis of a circular loop, far from the loop (distance x ≫ The dimensional formula of the magnetic field B (in SI units of tesla) is:A cyclotron of magnetic field B accelerates positive charges of mass m, charge q. The cyclTorque on a magnetic dipole (current loop) of moment m placed in a uniform field B at anglTwo long parallel wires carry currents I₁ and I₂ in the SAME direction, separated by dista