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The carbonyl group $\mathrm{C{=}O}$ is highly POLAR, with the oxygen bearing a partial negative charge and the carbon a partial positive charge. The principal consequence for the carbonyl group's reactivity is
Ait undergoes nucleophilic addition at the electrophilic carbon
Bit undergoes electrophilic addition at the oxygen
Cit does not react with any nucleophile
Dit is non-polar overall and behaves like a hydrocarbon
Answer & Solution
Correct answer: A. it undergoes nucleophilic addition at the electrophilic carbon
1. Oxygen is much more electronegative than carbon, so it pulls electron density away from the C in the $\mathrm{C{=}O}$ bond.
2. Result: the carbon carries a partial POSITIVE charge ($\delta^+$) and the oxygen carries a partial NEGATIVE charge ($\delta^-$).
3. The electrophilic ($\delta^+$) carbon is then attacked by NUCLEOPHILES — species with lone pairs or available electron density (such as $\mathrm{CN^-}$, $\mathrm{H^-}$ from $\mathrm{LiAlH_4}$, primary/secondary amines, alcohols).
4. This NUCLEOPHILIC ADDITION is the dominant reaction class for carbonyl compounds — the foundation of aldol condensations, cyanohydrin formation, hemiacetal/acetal formation, etc.
5. Option B is the alkene-style reactivity (electrophilic addition), which carbonyls do NOT typically undergo. Option C contradicts well-known carbonyl chemistry. Option D ignores the strong polarity confirmed by dipole moment measurements ($\sim 2.5\,\text{D}$ for many ketones).
_Source: NCERT Class 12 Chemistry Part 2, Ch 8, §8.1.2 + §8.4 (Carbonyl polarity, nucleophilic addition mechanism), p. 4 + p. 9._
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