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Pure silicon is doped with a small amount of PHOSPHORUS (a pentavalent element from group 15). The resulting semiconductor is
Aintrinsic, with $n_e = n_h$
Bp-type, with holes as majority carriers
Can insulator at all temperatures
Dn-type, with electrons as majority carriers
Answer & Solution
Correct answer: D. n-type, with electrons as majority carriers
1. NCERT §14.4 explains doping: a PENTAVALENT impurity (P, As, Sb) contributes ONE extra valence electron per atom to the silicon lattice (Si is tetravalent — group 14).
2. The fifth electron is loosely bound and easily released into the conduction band, even at room temperature.
3. The result is a semiconductor with MANY more electrons than holes — electrons are the MAJORITY carriers and holes are the MINORITY carriers. This is the n-TYPE semiconductor.
4. (The 'n' refers to the negative charge of the majority carriers; the material itself remains electrically neutral overall, because each donated electron leaves behind a fixed positive ion at the donor site.)
5. Option A would require equal carrier numbers (intrinsic, which doping breaks). Option B is p-type (created with trivalent dopants like boron). Option C is wrong — doping makes the semiconductor MORE conducting, not less.
_Source: NCERT Class 12 Physics Part 2, Ch 14, §14.4 (Extrinsic Semiconductor — (i) n-type), p. 7._
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