What is the sum of the **infinite** geometric series $1 + \dfrac{1}{2} + \dfrac{1}{4} + \dfrac{1}{8} + \dfrac{1}{16} + \ldots$?
A$2$
B$1.5$
CThe series diverges
D$1$
Answer & Solution
Correct answer: A. $2$
First confirm geometric, with $a_{1} = 1$ and $r = \dfrac{1}{2}$.
Since $|r| = 1/2 < 1$, the infinite sum converges:
$S_{\infty} = \dfrac{a_{1}}{1 - r} = \dfrac{1}{1 - 1/2} = \dfrac{1}{1/2} = 2$.
Intuition: each successive term halves the remaining gap to $2$. After $1 + 0.5 = 1.5$, you're $0.5$ short. After $+0.25$, you're $0.25$ short. The gap halves forever but never goes below zero.
- Trap A ($1$) returns just the first term.
- Trap B ($1.5$) returns the partial sum after two terms.
- Trap D would apply if $|r| \ge 1$.
This series ($1 + 1/2 + 1/4 + \ldots = 2$) is the most famous example of a convergent infinite geometric series and underlies Zeno's paradox.
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