What is the $20$th term of the arithmetic sequence with first term $a_{1} = 4$ and common difference $d = -3$?
A$-53$
B$-50$
C$61$
D$-47$
Answer & Solution
Correct answer: A. $-53$
$a_{n} = a_{1} + (n - 1)d$.
$a_{20} = 4 + (20 - 1)(-3) = 4 + 19 \cdot (-3) = 4 - 57 = -53$.
- Trap B ($-50 = 4 + 18(-3)$) uses $n - 2$.
- Trap C ($-47 = 4 - 51 + ...$) miscomputes $19 \cdot 3$.
- Trap D ($+61$) gets the sign of $d$ wrong.
When $d$ is negative, the sequence *decreases* — by term 20, the sequence has fallen $57$ units below $a_{1}$.
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