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In a triangle ABC, the Law of Sines states:
A$a/\sin A = b/\sin B = c/\sin C = 2R$
B$a^2 = b^2 + c^2 - 2bc \cos A$
C$\sin A + \sin B + \sin C = 1$
D$a + b + c = \sin A + \sin B + \sin C$
Answer & Solution
Correct answer: A. $a/\sin A = b/\sin B = c/\sin C = 2R$
Law of Sines: a/sin A = b/sin B = c/sin C = 2R (R = circumradius). The cosine formula is the Law of Cosines (B). The other options are not standard.
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