In a triangle ABC, the Law of Sines states:
A$a/\sin A = b/\sin B = c/\sin C = 2R$
B$a^2 = b^2 + c^2 - 2bc \cos A$
C$\sin A + \sin B + \sin C = 1$
D$a + b + c = \sin A + \sin B + \sin C$
Answer & Solution
Correct answer: A. $a/\sin A = b/\sin B = c/\sin C = 2R$
**Law of Sines:** a/sin A = b/sin B = c/sin C = 2R (R = circumradius).
The cosine formula is the Law of Cosines (B).
The other options are not standard.
Keep practising Trigonometric Functions
Browse all Trigonometric Functions questions for AP Intermediate 1st Year, or explore more Mathematics topics.