In a single-slit Fraunhofer diffraction pattern, the first minimum occ…

Question

In a single-slit Fraunhofer diffraction pattern, the first minimum occurs at angle $	heta$ satisfying:

Accepted Answer

B. $a\sin	heta = \lambda$

**First minimum:** $a\sin	heta = \lambda$ (slit divided into 2 halves, paths from extremes differ by $\lambda$ — pairs cancel).
Successive minima at $a\sin	heta = n\lambda$ (n = ±1, ±2, …)
central maximum is twice as wide as side fringes.

Answer

$a\sin	heta = \lambda/2$

Answer

$a\sin	heta = 2\lambda$

Answer

$a\sin	heta = n\lambda \cdot d/D$

In a single-slit Fraunhofer diffraction pattern, the first minimum occurs at angle $\theta$ satisfying:

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