alleryLight of intensity $I_0$ passes through two polarizers whose axes make 60° with each other. The transmitted intensity is:
A$I_0/8$
B$I_0/4$
C$I_0/2$
D$I_0 \cos^2 60°$
Answer & Solution
Correct answer: A. $I_0/8$
**First polarizer:** $I_0 \to I_0/2$ (unpolarized).
**Second polarizer (Malus):** $I_0/2 \times \cos^2 60° = I_0/2 \times 1/4 = I_0/8$.
Keep practising Wave Optics
Browse all Wave Optics questions for AP Intermediate 2nd Year, or explore more Physics topics.
Related questions
Polarisation of light is direct experimental evidence that light is a:The motional EMF induced in a conductor of length $\ell$ moving with velocity $v$ perpendiThe resolving power (RP) of a diffraction grating with N slits in the m-th order is:In Young's double-slit experiment, the fringe width β is given by:In Young's experiment, a BRIGHT fringe (constructive interference) requires path differencIn single-slit diffraction, the central maximum is:BREWSTER'S LAW for the polarising angle θ_B relates to the refractive index n as:NEET · Physics · Interference or Diffraction