Light of intensity $I_0$ passes through two polarizers whose axes make 60° with each other. The transmitted intensity is:
A$I_0/8$
B$I_0/4$
C$I_0/2$
D$I_0 \cos^2 60°$
Answer & Solution
Correct answer: A. $I_0/8$
First polarizer: $I_0 \to I_0/2$ (unpolarized). Second polarizer (Malus): $I_0/2 \times \cos^2 60° = I_0/2 \times 1/4 = I_0/8$.
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