Simplify $\dfrac{x^{8}}{x^{3}}$ for $x \ne 0$.
A$x^{5}$
B$x^{11}$
C$x^{\frac{8}{3}}$
D$x^{24}$
Answer & Solution
Correct answer: A. $x^{5}$
Apply the quotient rule for exponents: $\dfrac{x^{a}}{x^{b}} = x^{a - b}$.
$\dfrac{x^{8}}{x^{3}} = x^{8 - 3} = x^{5}$.
- Trap B ($x^{11}$) adds exponents (product rule misused for quotient).
- Trap C ($x^{8/3}$) divides exponents — wrong operation.
- Trap D ($x^{24}$) multiplies exponents (power rule misused).
Mnemonic: the four basic exponent operations — *same base*:
- Product: $x^{a} \cdot x^{b} = x^{a+b}$ — exponents **add**.
- Quotient: $\dfrac{x^{a}}{x^{b}} = x^{a-b}$ — exponents **subtract**.
- Power: $(x^{a})^{b} = x^{ab}$ — exponents **multiply**.
- Roots: $\sqrt[n]{x^{a}} = x^{a/n}$ — exponents **divide**.
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