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The area enclosed by the parabola $y^2 = 4ax$ and its latus rectum is:
A$2a^2$, the latus rectum length times unit width on chart
B$4a^2/3$, half the correct value on the school chart here
C$\pi a^2$, the wrong formula treating it as a circle
D$8a^2/3$, the standard result of the school chart calculation
Answer & Solution
Correct answer: D. $8a^2/3$, the standard result of the school chart calculation
Area between parabola $y^2 = 4ax$ and its latus rectum = $8a^2/3$.
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