In the Bohr model, the radius of the $n$th orbit of hydrogen scales as:
A$n^2 a_0$, since $r_n = n^2 a_0$ with $a_0 = 0.529$ Å
B$n a_0$, the linear scaling with quantum number here
C$a_0/n^2$, with the orbit shrinking for higher levels
D$a_0/n$, the simple inverse scaling with $n$ alone
Answer & Solution
Correct answer: A. $n^2 a_0$, since $r_n = n^2 a_0$ with $a_0 = 0.529$ Å
Bohr radii scale as $n^2$: $r_n = n^2 a_0$.
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