alleryStart learning →Find the vertex of the parabola $y = x^2 - 2x - 3$.
A$(0, -3)$
B$(1, -4)$
C$(-1, 0)$
D$(2, -3)$
Answer & Solution
Correct answer: B. $(1, -4)$
Factoring gives $(x - 3)(x + 1) = 0$, so the x-intercepts are $-1$ and $3$.
The axis of symmetry sits midway, at $x = 1$.
Substitute $x = 1$ into $y = x^2 - 2x - 3$: $y = 1 - 2 - 3 = -4$.
So the vertex is $(1, -4)$.
**Option A is the y-intercept, not the vertex.**
Related questions
The graph of $f(x) = |x| + 2$ is the graph of $y = |x|$ shifted in which direction?A line has slope 2. What is the slope of any line perpendicular to it?Find the distance between the points $Q(-2, -3)$ and $R(4, 1.5)$ in the xy-plane.If 10000 rupees is invested at a simple annual interest rate of 6 percent, what is the valMachine A produces a batch in 3 hours; machine B produces the same batch in 2 hours. How lA 12g mixture is 40% vinegar by weight. How many grams of oil must be added so the new mixEllen has three exam scores 82, 74, and 90. What score on her next exam will give her an aWhat is the domain of the function $g(x) = x^3 + qrt{x + 2} - 10$?