Solve the system $4x + 3y = 13$ and $x + 2y = 2$ for $(x, y)$.
A$(2, 1)$
B$(-1, 4)$
C$(0, 1)$
D$(4, -1)$
Answer & Solution
Correct answer: D. $(4, -1)$
Use substitution: from $x + 2y = 2$, $x = 2 - 2y$. Substitute into the first equation: $4(2 - 2y) + 3y = 13$, so $8 - 8y + 3y = 13$, giving $-5y = 5$ and $y = -1$. Then $x = 2 - 2(-1) = 4$. The pair $(4, -1)$ satisfies both equations.
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