Using the identity $a^2 - b^2 = (a+b)(a-b)$, simplify $\frac{x^2 - 9}{4x - 12}$ for $x \neq 3$.
A$\frac{x - 3}{4}$
B$\frac{x^2}{4x}$
C$\frac{4}{x + 3}$
D$\frac{x + 3}{4}$
Answer & Solution
Correct answer: D. $\frac{x + 3}{4}$
Factor numerator with the difference of squares: $x^2 - 9 = (x+3)(x-3)$. Factor denominator: $4x - 12 = 4(x - 3)$. Cancel the shared factor $(x-3)$ for $x \neq 3$, leaving $(x+3)/4$. Option A drops the wrong factor; option C inverts numerator and denominator.
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