For an ideal integrator built with an op-amp (input R, feedback C), the output is which transformation of input?
AV_out(t) = -(1/RC)·∫ V_in(t) dt
BV_out(t) = -(RC)·dV_in/dt always
CV_out(t) = +V_in(t)·RC always
DV_out(t) = -V_in(t)/RC always
Answer & Solution
Correct answer: A. V_out(t) = -(1/RC)·∫ V_in(t) dt
Inverting integrator: I_R = V_in/R; capacitor I = C·dV/dt; equating gives V_out = -(1/RC)·∫V_in dt. Differentiator is the R/C swap.
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