Home › MHT-CET › Physics › Electromagnetic Induction › Mutual inductance $M$ between two coils satisfies:
Mutual inductance $M$ between two coils satisfies:
A$M_{12} \ne M_{21}$ always
B$M_{12} = M_{21}$ by symmetry
C$M_{12} = M_{21}^2$
D$M_{12} = -M_{21}$
Answer & Solution
Correct answer: B. $M_{12} = M_{21}$ by symmetry
By the symmetry of the mutual-inductance integral (Neumann formula), $M_{12} = M_{21} \equiv M$. So you can compute it whichever way is easier — flux in coil 2 per unit current in coil 1, or vice versa.
Related questions
When a rod moves perpendicular to a magnetic field at constant velocity, the FREE charges An LC circuit oscillates with angular frequency ω equal to:Maxwell's correction to Ampère's law introduced:A bar magnet is dropped through a vertical conducting ring. The magnet:A coil of inductance 0.5 H carries a current changing at 4 A s⁻¹. The induced EMF is:A magnetic flux through a coil changes from 4 Wb to 1 Wb in 0.3 s. The average EMF inducedEddy currents are reduced in transformer cores by:A transformer works on the principle of: