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The induced EMF in a coil due to changing current in itself is given by:

A$e = -L\,dI/dt$
B$e = +L\,dI/dt$
C$e = L/I$
D$e = L \cdot I$
Answer & Solution
Correct answer: A. $e = -L\,dI/dt$
Self-induced EMF: $e = -L\,dI/dt$. The minus sign (Lenz) means it opposes the change in current, hence the description of self-inductance as 'electrical inertia'.
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