Home › CBSE Class 11 › Physics › Motion in a Plane › Per NCERT §3.9 eqn 3.41, the maximum height h_m …
Per NCERT §3.9 eqn 3.41, the maximum height h_m of a projectile is which expression?
A(v₀ sin θ₀)² / (2g)
Bv₀² / (2g)
Cv₀² sin 2θ₀ / g
D(v₀ cos θ₀)² / (2g)
Answer & Solution
Correct answer: A. (v₀ sin θ₀)² / (2g)
NCERT eqn 3.41: h_m = (v₀ sin θ₀)² / (2g).
Related questions
The time for one full revolution is the:Centripetal acceleration has constant magnitude but is not a constant vector because its:Newton named the centre-directed acceleration:The acceleration in uniform circular motion always points:A car goes round a roundabout at a steady 20 km/h. Its motion is:For a fixed launch speed, range is greatest at a launch angle of:The horizontal distance from launch to where the projectile lands back at the same level iTime of flight is twice the time to reach maximum height because the path is: