Home › NEET UG › Chemistry › Chemical Bonding and Molecular Structure ›  In the molecular geometries shown for AB₂, AB₃, AB₄, AB₅ and AB₆ (with no lone pair on A), the central-atom bond angles are respectively:
A90°, 120°, 109.5°, 180°, 120°
B180°, 120°, 109.5°, 90/120°, 90°
C120°, 109.5°, 90°, 180°, 120°
D109.5°, 120°, 180°, 90°, 90°
Answer & Solution
Correct answer: B. 180°, 120°, 109.5°, 90/120°, 90°
Linear (AB₂) → 180°. Trigonal planar (AB₃) → 120°. Tetrahedral (AB₄) → 109.5°. Trigonal bipyramidal (AB₅) → 90° axial-equatorial / 120° equatorial-equatorial. Octahedral (AB₆) → 90°.
Related questions
Besides VSEPR and the Kossel Lewis approach, which two theories are listed?Which theory is abbreviated VSEPR?Why can lattice enthalpy not be calculated directly from attraction and repulsion alone?Ionic bonds form most easily between elements with low ionization enthalpies and high negaWhat is the lattice enthalpy of sodium chloride?Lattice enthalpy is the energy required to separate one mole of an ionic solid into:The structures contributing to a resonance hybrid are called:Why was the concept of resonance introduced?