For a zero-order reaction $A \to P$, the integrated rate law is $[A]_t = [A]_0 - kt$. If initial $[A]_0 = 1.0$ M and after 200 s, $[A] = 0.6$ M, then $k$ equals:
A$0.4$ M⁻¹ s⁻¹
B$2 \times 10^{-4}$ M s⁻¹
C$2 \times 10^{-3}$ M s⁻¹
D$5 \times 10^{-3}$ s⁻¹
Answer & Solution
Correct answer: C. $2 \times 10^{-3}$ M s⁻¹
$k = ([A]_0 - [A]_t)/t = (1.0 - 0.6)/200 = 0.4/200 = 2\times10^{-3}$ M s⁻¹. Units of M s⁻¹ confirm zero order.
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