Consider $2A + 2B \to 2C + D$. Doubling [A] at constant [B] quadruples the rate; doubling [B] at constant [A] doubles the rate. The rate law is:
Arate = $k[A][B]^2$
Brate = $k[A][B]$
Crate = $k[A]^2[B]$
Drate = $k[A]^2[B]^2$
Answer & Solution
Correct answer: C. rate = $k[A]^2[B]$
[A] × 2 ⇒ rate × 4 = 2² → order in A = 2. [B] × 2 ⇒ rate × 2 → order in B = 1. Rate = $k[A]^2[B]$ (overall order 3).
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