Michaela has $\$2.05$ in dimes and nickels. She has **seven more dimes than nickels**. How many nickels does she have?

Let $n$ be the number of nickels. Then $n + 7$ is the number of dimes. Total value: $0.05 n + 0.10 (n + 7) = 2.05$. Distribute: $0.05 n + 0.10 n + 0.70 = 2.05$. Combine: $0.15 n + 0.70 = 2.05$. Subtract $0.70$: $0.15 n = 1.35$. Divide: $n = 9$. So Michaela has $9$ nickels (and $9 + 7 = 16$ dimes). Check: $9(0.05) + 16(0.10) = 0.45 + 1.60 = \$2.05$ ✓. - Trap D ($16$) is the number of **dimes**, not nickels. The question asks for nickels. - Trap A ($7$) is the constant from the problem.