The centroid of the tetrahedron with vertices $A(3, -5, 7),\ B(5, 4, 2),\ C(7, -7, -3),\ D(1, 0, 2)$ is:
A$(4, -2, 2)$
B$(16, -8, 8)$
C$(4, -4, 2)$
D$(5, -2, 3)$
Answer & Solution
Correct answer: A. $(4, -2, 2)$
$G = (A+B+C+D)/4 = ((3+5+7+1)/4, (-5+4-7+0)/4, (7+2-3+2)/4) = (16/4, -8/4, 8/4) = (4, -2, 2)$.
Related questions
Vector $PQ$ has magnitude 5 units and is inclined at $150^{\circ}$ to the $x$-axis. In theForces $2i-5j+6k$ and $-i-2j-k$ move a particle from $A(4,-3,-2)$ to $B(6,-1,-3)$. The worPosition vectors $2i-j+k$, $i-3j-5k$ and $3i-4j-4k$ form a triangle with sides $ qrt{41}$,When are two vectors counted as equal?What is the magnitude of the position vector with components 9 and 12?Which two features identify a vector?The work done by a constant force F in displacement d isIf a, b, c are mutually perpendicular unit vectors, the value of a · (b × c) is