The distance from the point $P(2, 3, 4)$ to the **x-axis** is:
A2
B3
C5
D$\sqrt{29}$
Answer & Solution
Correct answer: C. 5
Distance from $(x, y, z)$ to the x-axis equals $\sqrt{y^2 + z^2} = \sqrt{9 + 16} = \sqrt{25} = 5$. (To the XY-plane it would be $|z| = 4$; to the origin $\sqrt{29}$.)
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