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If P = {m, n} and Q = {n, m}, then P × Q equals
A{(m, n)}
B{(m, n), (n, m)}
C{(m, m), (m, n), (n, m), (n, n)}
D{(m, m), (n, n)}
Answer & Solution
Correct answer: C. {(m, m), (m, n), (n, m), (n, n)}
P and Q are equal as sets ({m, n}), so P × Q = {m, n} × {m, n} = {(m, m), (m, n), (n, m), (n, n)} — four ordered pairs, not two.
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