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Which identity is ALWAYS TRUE for arbitrary sets A, B, C?
A(A × B) ∪ C = A × (B ∪ C)
BA × (B ∪ C) = (A × B) ∪ (A × C)
CA × (B ∪ C) = (A ∪ B) × C
DA × (B ∩ C) = (A ∩ B) × C
Answer & Solution
Correct answer: B. A × (B ∪ C) = (A × B) ∪ (A × C)
Cartesian product distributes over union: A × (B ∪ C) = (A × B) ∪ (A × C). The other options mix product and union/intersection illegally.
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