One number is **ten more than twice** another number. Their sum is $1$. What is the **second** (larger) number?

Let $x$ be the first (smaller) number. The second is $2x + 10$. Their sum equals $1$: $x + (2x + 10) = 1$ $3x + 10 = 1$ $3x = -9$ $x = -3$ (first number). Second number: $2(-3) + 10 = -6 + 10 = 4$. Check: "ten more than twice $-3$" is $2(-3) + 10 = 4$ ✓. And $-3 + 4 = 1$ ✓. The question asks for the **second** (larger) number, so the answer is $\boxed{4}$. - Trap A ($-3$) is the *first* number — the trap of answering with the wrong one of the pair. - Traps B and D do not satisfy both constraints. Read carefully: "What is the second number?" — knowing which of the two is asked for is half the work.