One number is **five more than** another number. The sum of the two numbers is $21$. What are the two numbers?

Let $n$ be the first number. The second number is $n + 5$ (five more than the first). Their sum is $21$: $n + (n + 5) = 21$ $2n + 5 = 21$ $2n = 16$ $n = 8$, and the second number is $8 + 5 = 13$. Check: $8 + 13 = 21$ ✓ and $13$ is $5$ more than $8$ ✓. - Trap A ($5$ and $16$) sums to $21$ but the difference is $11$, not $5$. - Trap C sums to $25$, not $21$. - Trap D sums to $21$ but the second number is $1$ less than the first, not $5$ more. Both conditions must hold simultaneously — only one pair satisfies both.