The graph above shows the two linear equations $\quad 4x + 3y = 13$ $\quad x + 2y = 2$ graphed in the $xy$-plane. From the graph, what is the **solution** of the system (i.e. the $(x, y)$ pair satisfying both equations)?

The solution of a system of two linear equations corresponds to the **intersection point** of the two graphed lines. From the figure, the lines cross at $(4, -1)$. Algebraic check (using substitution): From $x + 2y = 2$, $x = 2 - 2y$. Substitute into $4x + 3y = 13$: $4(2 - 2y) + 3y = 13 \Rightarrow 8 - 8y + 3y = 13 \Rightarrow -5y = 5 \Rightarrow y = -1$. Then $x = 2 - 2(-1) = 4$. So the solution is $(4, -1)$ ✓ — matching the graph. - Trap A swaps the coordinates and signs. - Trap B is the $y$-intercept of the first line alone, not the intersection. - Trap D is the $x$-intercept of the second line alone, not the intersection. This question is figure-anchored because the prompt asks you to read the intersection *from the graph* — though the algebra confirms the same point.