A line has slope $0.75$ and passes through the point $(-2, -3)$. What is the equation of the line in slope-intercept form?

Slope-intercept form: $y = mx + b$. Here $m = 0.75$, so the line is $y = 0.75x + b$ for some $b$. Substitute the known point $(-2, -3)$: $-3 = 0.75 \cdot (-2) + b$ $-3 = -1.5 + b$ $b = -3 + 1.5 = -1.5$. So the line is $y = 0.75x - 1.5$. - Trap B flips the sign of $b$. - Trap C uses the point's $y$-coordinate ($-3$) directly as the intercept — but $(-2, -3)$ is **not** on the $y$-axis, so $-3$ is *not* the intercept. - Trap D applies $0.75 \cdot (-2) = -1.5$ but adds it to $-3$ instead of subtracting from $-3$.