What is the slope of the line passing through the points $Q(-2, -3)$ and $R(4, 1.5)$?

Slope $= \dfrac{\text{rise}}{\text{run}} = \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}$. Using $Q(-2, -3)$ as $(x_{1}, y_{1})$ and $R(4, 1.5)$ as $(x_{2}, y_{2})$: Slope $= \dfrac{1.5 - (-3)}{4 - (-2)} = \dfrac{4.5}{6} = 0.75$. - Trap A ($-0.75$) flips the sign — common when one of the negative coordinates is mishandled, e.g. subtracting $-3$ from $1.5$ as $1.5 - 3$. - Trap B ($0.5$) computes $\dfrac{3}{6}$, dropping the half from $1.5$. - Trap D ($1.33 \approx 6/4.5$) inverts rise and run.