In the $xy$-plane, what is the distance between the points $Q(-2, -3)$ and $R(4, 1.5)$?
A$7.5$
B$6$
C$4.5$
D$\sqrt{56.25} \cdot 2$
Answer & Solution
Correct answer: A. $7.5$
Construct a right triangle with hypotenuse $QR$ by dropping a vertical line from $R$ and a horizontal line from $Q$. The legs of the triangle have lengths:
- Horizontal: $4 - (-2) = 6$.
- Vertical: $1.5 - (-3) = 4.5$.
By the Pythagorean theorem,
$QR = \sqrt{6^{2} + 4.5^{2}} = \sqrt{36 + 20.25} = \sqrt{56.25} = 7.5$.
- Trap A ($4.5$) and Trap B ($6$) each give a *leg* length, not the hypotenuse.
- Trap D doubles the correct value.
The distance formula $d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}$ is just the Pythagorean theorem applied to coordinates.
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